3.3.36 \(\int \frac {(b x+c x^2)^2}{d+e x} \, dx\) [236]

Optimal. Leaf size=93 \[ -\frac {d (c d-b e)^2 x}{e^4}+\frac {(c d-b e)^2 x^2}{2 e^3}-\frac {c (c d-2 b e) x^3}{3 e^2}+\frac {c^2 x^4}{4 e}+\frac {d^2 (c d-b e)^2 \log (d+e x)}{e^5} \]

[Out]

-d*(-b*e+c*d)^2*x/e^4+1/2*(-b*e+c*d)^2*x^2/e^3-1/3*c*(-2*b*e+c*d)*x^3/e^2+1/4*c^2*x^4/e+d^2*(-b*e+c*d)^2*ln(e*
x+d)/e^5

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Rubi [A]
time = 0.06, antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {712} \begin {gather*} \frac {d^2 (c d-b e)^2 \log (d+e x)}{e^5}-\frac {d x (c d-b e)^2}{e^4}+\frac {x^2 (c d-b e)^2}{2 e^3}-\frac {c x^3 (c d-2 b e)}{3 e^2}+\frac {c^2 x^4}{4 e} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b*x + c*x^2)^2/(d + e*x),x]

[Out]

-((d*(c*d - b*e)^2*x)/e^4) + ((c*d - b*e)^2*x^2)/(2*e^3) - (c*(c*d - 2*b*e)*x^3)/(3*e^2) + (c^2*x^4)/(4*e) + (
d^2*(c*d - b*e)^2*Log[d + e*x])/e^5

Rule 712

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d +
e*x)^m*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*
e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && IntegerQ[p] && (GtQ[p, 0] || (EqQ[a, 0] && IntegerQ[m]))

Rubi steps

\begin {align*} \int \frac {\left (b x+c x^2\right )^2}{d+e x} \, dx &=\int \left (-\frac {d (c d-b e)^2}{e^4}+\frac {(-c d+b e)^2 x}{e^3}-\frac {c (c d-2 b e) x^2}{e^2}+\frac {c^2 x^3}{e}+\frac {d^2 (c d-b e)^2}{e^4 (d+e x)}\right ) \, dx\\ &=-\frac {d (c d-b e)^2 x}{e^4}+\frac {(c d-b e)^2 x^2}{2 e^3}-\frac {c (c d-2 b e) x^3}{3 e^2}+\frac {c^2 x^4}{4 e}+\frac {d^2 (c d-b e)^2 \log (d+e x)}{e^5}\\ \end {align*}

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Mathematica [A]
time = 0.03, size = 106, normalized size = 1.14 \begin {gather*} -\frac {d (c d-b e)^2 x}{e^4}+\frac {(-c d+b e)^2 x^2}{2 e^3}-\frac {c (c d-2 b e) x^3}{3 e^2}+\frac {c^2 x^4}{4 e}+\frac {\left (c^2 d^4-2 b c d^3 e+b^2 d^2 e^2\right ) \log (d+e x)}{e^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b*x + c*x^2)^2/(d + e*x),x]

[Out]

-((d*(c*d - b*e)^2*x)/e^4) + ((-(c*d) + b*e)^2*x^2)/(2*e^3) - (c*(c*d - 2*b*e)*x^3)/(3*e^2) + (c^2*x^4)/(4*e)
+ ((c^2*d^4 - 2*b*c*d^3*e + b^2*d^2*e^2)*Log[d + e*x])/e^5

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Maple [A]
time = 0.50, size = 135, normalized size = 1.45

method	result	size
norman	\(\frac {c^{2} x^{4}}{4 e}+\frac {\left (b^{2} e^{2}-2 b c d e +d^{2} c^{2}\right ) x^{2}}{2 e^{3}}-\frac {d \left (b^{2} e^{2}-2 b c d e +d^{2} c^{2}\right ) x}{e^{4}}+\frac {c \left (2 b e -c d \right ) x^{3}}{3 e^{2}}+\frac {d^{2} \left (b^{2} e^{2}-2 b c d e +d^{2} c^{2}\right ) \ln \left (e x +d \right )}{e^{5}}\)	\(122\)
default	\(-\frac {-\frac {c^{2} x^{4} e^{3}}{4}+\frac {\left (-\left (b e -c d \right ) e^{2} c -e^{3} b c \right ) x^{3}}{3}+\frac {\left (-\left (b e -c d \right ) b \,e^{2}+c e \left (b d e -c \,d^{2}\right )\right ) x^{2}}{2}+\left (b e -c d \right ) \left (b d e -c \,d^{2}\right ) x}{e^{4}}+\frac {d^{2} \left (b^{2} e^{2}-2 b c d e +d^{2} c^{2}\right ) \ln \left (e x +d \right )}{e^{5}}\)	\(135\)
risch	\(\frac {c^{2} x^{4}}{4 e}+\frac {2 x^{3} b c}{3 e}-\frac {c^{2} d \,x^{3}}{3 e^{2}}+\frac {x^{2} b^{2}}{2 e}-\frac {x^{2} d b c}{e^{2}}+\frac {x^{2} d^{2} c^{2}}{2 e^{3}}-\frac {b^{2} d x}{e^{2}}+\frac {2 b c \,d^{2} x}{e^{3}}-\frac {c^{2} d^{3} x}{e^{4}}+\frac {d^{2} \ln \left (e x +d \right ) b^{2}}{e^{3}}-\frac {2 d^{3} \ln \left (e x +d \right ) b c}{e^{4}}+\frac {d^{4} \ln \left (e x +d \right ) c^{2}}{e^{5}}\)	\(152\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+b*x)^2/(e*x+d),x,method=_RETURNVERBOSE)

[Out]

-1/e^4*(-1/4*c^2*x^4*e^3+1/3*(-(b*e-c*d)*e^2*c-e^3*b*c)*x^3+1/2*(-(b*e-c*d)*b*e^2+c*e*(b*d*e-c*d^2))*x^2+(b*e-
c*d)*(b*d*e-c*d^2)*x)+d^2*(b^2*e^2-2*b*c*d*e+c^2*d^2)/e^5*ln(e*x+d)

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Maxima [A]
time = 0.27, size = 126, normalized size = 1.35 \begin {gather*} {\left (c^{2} d^{4} - 2 \, b c d^{3} e + b^{2} d^{2} e^{2}\right )} e^{\left (-5\right )} \log \left (x e + d\right ) + \frac {1}{12} \, {\left (3 \, c^{2} x^{4} e^{3} - 4 \, {\left (c^{2} d e^{2} - 2 \, b c e^{3}\right )} x^{3} + 6 \, {\left (c^{2} d^{2} e - 2 \, b c d e^{2} + b^{2} e^{3}\right )} x^{2} - 12 \, {\left (c^{2} d^{3} - 2 \, b c d^{2} e + b^{2} d e^{2}\right )} x\right )} e^{\left (-4\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^2/(e*x+d),x, algorithm="maxima")

[Out]

(c^2*d^4 - 2*b*c*d^3*e + b^2*d^2*e^2)*e^(-5)*log(x*e + d) + 1/12*(3*c^2*x^4*e^3 - 4*(c^2*d*e^2 - 2*b*c*e^3)*x^
3 + 6*(c^2*d^2*e - 2*b*c*d*e^2 + b^2*e^3)*x^2 - 12*(c^2*d^3 - 2*b*c*d^2*e + b^2*d*e^2)*x)*e^(-4)

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Fricas [A]
time = 1.66, size = 130, normalized size = 1.40 \begin {gather*} -\frac {1}{12} \, {\left (12 \, c^{2} d^{3} x e - {\left (3 \, c^{2} x^{4} + 8 \, b c x^{3} + 6 \, b^{2} x^{2}\right )} e^{4} + 4 \, {\left (c^{2} d x^{3} + 3 \, b c d x^{2} + 3 \, b^{2} d x\right )} e^{3} - 6 \, {\left (c^{2} d^{2} x^{2} + 4 \, b c d^{2} x\right )} e^{2} - 12 \, {\left (c^{2} d^{4} - 2 \, b c d^{3} e + b^{2} d^{2} e^{2}\right )} \log \left (x e + d\right )\right )} e^{\left (-5\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^2/(e*x+d),x, algorithm="fricas")

[Out]

-1/12*(12*c^2*d^3*x*e - (3*c^2*x^4 + 8*b*c*x^3 + 6*b^2*x^2)*e^4 + 4*(c^2*d*x^3 + 3*b*c*d*x^2 + 3*b^2*d*x)*e^3
- 6*(c^2*d^2*x^2 + 4*b*c*d^2*x)*e^2 - 12*(c^2*d^4 - 2*b*c*d^3*e + b^2*d^2*e^2)*log(x*e + d))*e^(-5)

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Sympy [A]
time = 0.14, size = 116, normalized size = 1.25 \begin {gather*} \frac {c^{2} x^{4}}{4 e} + \frac {d^{2} \left (b e - c d\right )^{2} \log {\left (d + e x \right )}}{e^{5}} + x^{3} \cdot \left (\frac {2 b c}{3 e} - \frac {c^{2} d}{3 e^{2}}\right ) + x^{2} \left (\frac {b^{2}}{2 e} - \frac {b c d}{e^{2}} + \frac {c^{2} d^{2}}{2 e^{3}}\right ) + x \left (- \frac {b^{2} d}{e^{2}} + \frac {2 b c d^{2}}{e^{3}} - \frac {c^{2} d^{3}}{e^{4}}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+b*x)**2/(e*x+d),x)

[Out]

c**2*x**4/(4*e) + d**2*(b*e - c*d)**2*log(d + e*x)/e**5 + x**3*(2*b*c/(3*e) - c**2*d/(3*e**2)) + x**2*(b**2/(2
*e) - b*c*d/e**2 + c**2*d**2/(2*e**3)) + x*(-b**2*d/e**2 + 2*b*c*d**2/e**3 - c**2*d**3/e**4)

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Giac [A]
time = 1.18, size = 134, normalized size = 1.44 \begin {gather*} {\left (c^{2} d^{4} - 2 \, b c d^{3} e + b^{2} d^{2} e^{2}\right )} e^{\left (-5\right )} \log \left ({\left | x e + d \right |}\right ) + \frac {1}{12} \, {\left (3 \, c^{2} x^{4} e^{3} - 4 \, c^{2} d x^{3} e^{2} + 6 \, c^{2} d^{2} x^{2} e - 12 \, c^{2} d^{3} x + 8 \, b c x^{3} e^{3} - 12 \, b c d x^{2} e^{2} + 24 \, b c d^{2} x e + 6 \, b^{2} x^{2} e^{3} - 12 \, b^{2} d x e^{2}\right )} e^{\left (-4\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^2/(e*x+d),x, algorithm="giac")

[Out]

(c^2*d^4 - 2*b*c*d^3*e + b^2*d^2*e^2)*e^(-5)*log(abs(x*e + d)) + 1/12*(3*c^2*x^4*e^3 - 4*c^2*d*x^3*e^2 + 6*c^2
*d^2*x^2*e - 12*c^2*d^3*x + 8*b*c*x^3*e^3 - 12*b*c*d*x^2*e^2 + 24*b*c*d^2*x*e + 6*b^2*x^2*e^3 - 12*b^2*d*x*e^2
)*e^(-4)

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Mupad [B]
time = 0.05, size = 141, normalized size = 1.52 \begin {gather*} x^2\,\left (\frac {b^2}{2\,e}+\frac {d\,\left (\frac {c^2\,d}{e^2}-\frac {2\,b\,c}{e}\right )}{2\,e}\right )-x^3\,\left (\frac {c^2\,d}{3\,e^2}-\frac {2\,b\,c}{3\,e}\right )+\frac {c^2\,x^4}{4\,e}+\frac {\ln \left (d+e\,x\right )\,\left (b^2\,d^2\,e^2-2\,b\,c\,d^3\,e+c^2\,d^4\right )}{e^5}-\frac {d\,x\,\left (\frac {b^2}{e}+\frac {d\,\left (\frac {c^2\,d}{e^2}-\frac {2\,b\,c}{e}\right )}{e}\right )}{e} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x + c*x^2)^2/(d + e*x),x)

[Out]

x^2*(b^2/(2*e) + (d*((c^2*d)/e^2 - (2*b*c)/e))/(2*e)) - x^3*((c^2*d)/(3*e^2) - (2*b*c)/(3*e)) + (c^2*x^4)/(4*e
) + (log(d + e*x)*(c^2*d^4 + b^2*d^2*e^2 - 2*b*c*d^3*e))/e^5 - (d*x*(b^2/e + (d*((c^2*d)/e^2 - (2*b*c)/e))/e))
/e

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